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Calculate dead load in design report based on IS code and apply dead load on the model APPICATION OF DEAD LOAD ON THE MODEL. Finishes of 50mm dead load of finishing …
Mohammad Eqbal
updated on 27 Jan 2023
APPICATION OF DEAD LOAD ON THE MODEL.
dead load of finishing
0.05*24= 1.2 kn/m2
Dead load of slab = 0.15*25= 3.5kn/m^2
DEAD LOAD OF BRICK WALL THIICKNESS( 150MM) = 0.15*3*20= 9 KN/M
DEAD LOAD
FOR INDUSTRIAL BUIDIN
TOILET AND BATHROOM = 2KN/M2
CORRIDOR,PSSAG , STAIRCASE=5KN/M2
KITCHEN = 3N/M2
EQUPMENT ROO= 10KN/M2
ROOF DEPEND UPON THE ACCESSEBLE AND NON ASSECELE
ACCESS= 1.5 KN/M2
NON ASSECCEBLE = 0.75 KN/M2
APPICATION OF LIVE LOAD ON THE MODEL.
ASSUME THE COLUNM DISTANCE BETWEEN GAINTRY RAILS IS = 18 M
LOADING CAPACITY OF CRANE= 50 KN
WEIGHT OF CRAB= 40 KN
MAXIMUM WHEEL LOAD ON THE CRANE =
POINT LOAD ACTING ON THE SPAN DISTANT 1M FROM END = 50 KN
SELF WEEIGT OF CRANE INCLUDING CRAB ACTS UDL ON THE SPAN OF 10 M= 40 /18= 2.23 KN/M
Ra*18= 50*17+4*18*18/2
= 83 KN
Rb= 7.14 kn
take maximum value
Ra= 83 kn
SO LOAD ON EACH OF THE WHEEL= 83/2= 41.5 KN
MAXIMUM BENDING MOMENT DUE TO WHEEL LOAD ON COLUMN OF DISTANCE 10M =
TAKE MOENT ABOUT D
Rc*10= 41.5*6.5+41.5*4.5+2.4*10*5
Rc =57.64 kn
Rd =49.4 kn
bending moent uner whee due to rection RD= 49.4*4.5=222 kn-m
bending moent due to to impact= 0.1* 222= 22.5 kn-m
so total bendig moment = 22.5+222=244.5 kn-m 34.5kn-m
bending moment due to dead load = wl2/2 =2.4*10*5 =120kn-m
maximum bending moment =344.5 kn-m
MAXIMM SHEAR FORCE
FOR MAXIMUMSHEAR FORCE OE O THE WHEEL SOULD BE AT THE SUPPORT
Rc*10= 41.5*10+41.5* (10-2)
=415+332
Rc =74.7 KN
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