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  1. Home/
  2. Sanjay Jagadeshwara E/
  3. Structural dynamics

Structural dynamics

ANSWER 1 STATIC ANALYSIS : LOAD IS NOT VARIABLE WITH TIME AND NEGLECTED DUE TO SLOW APPLYING OF LOAD  MOTION OF THE STRUCTURE CAN BE DISEGARDED  THERE IS NO NECESSITY TO COUNT INTERIA AND DAMPING FORCES IN CASE OF STATIC ANALYSIS , BUT THE ELASTIC FORCE SHOULD BE ACCOUNTED. THERE IS NO INTERIA EFFECT ON STATIC…

    • Sanjay Jagadeshwara E

      updated on 02 Mar 2023

    ANSWER 1

    STATIC ANALYSIS :

    • LOAD IS NOT VARIABLE WITH TIME AND NEGLECTED DUE TO SLOW APPLYING OF LOAD 
    • MOTION OF THE STRUCTURE CAN BE DISEGARDED 
    • THERE IS NO NECESSITY TO COUNT INTERIA AND DAMPING FORCES IN CASE OF STATIC ANALYSIS , BUT THE ELASTIC FORCE SHOULD BE ACCOUNTED.
    • THERE IS NO INTERIA EFFECT ON STATIC ANALYSIS.

    DYNAMIC ANALSIS: 

    • LOAD IS VARIABLE WITH TIME DUE TO FAST APPLYING OF LOAD AND VIBRATION .
    • MOTION CAN NOT BE  DISREGARDED ( CAN'T BE CONSIDERED AS STATIC .) 
    • INTERIA AND DAMPING FORCES SHOULD BE ACCOUNTED FOR THE CALCULATION OF DYNAMIC ANALYSIS .
    • INTERIA EFFECT IS CONSIDERED IN DYANMIC ANALYSIS .

     ANSWER 2: EXPLAIN THE FOLLOWING WITH RELEVANT FORCE DISPLACMENT GRAPH:

    a) ELASTIC BEHAVIOR.

    b)INELASTIC BEHAVIOR .

    c) PLASTIC BEHAVIOR .

    d) NON-LINEAR INELASTIC BEHAVIOR .

     

    BELOW IS THE FORCE -DISPLACEMENT GRAPH EXTRACTED  FROM DYNAMIC OF STRUCTURES THEORY AND APPLICATION TO EARTHQUAKE ENGINEERING A.K CHOPRA WITH THE FOLLOWING EXPALNATION OF THE LISTED BEHAVIOR : 

     

     

    1) ELASTIC BEHAVIOR : ELASTIC BEHAVIOR IS THE PROPERTY OF THE MATERIAL UPTO WHICH THE MATERIAL CAN REATAIN IT'S SHAPE .FROM THE ABOVE MENTION THE GRAPH IT IS CLEARLY MENTIONED THAT  UPTO A CERTAIN POINT FROM "O" THE GRAPH IS LINEAR AND SHOWN ITS ELASTIC PROPERTIES .

    2) INELASTIC BEHAVIOR : INELASTIC BEHAVIOR IS THE PROPERTY OF THE MATERIAL WHEN THE MATERIAL CAN'T RETAIN IT'S PREVIOUS SHAPE AFTER A CERTAIN DEFORMATION .IN THE ABOVE MENTIONED GRAPH INELASTIC BEHAVIOR HAS BEEN SHOWN IN THE UPPER SHAPE OF THE CURVE UPTO POINT "a" .

    3) PLASTIC BEHAVIOR : PLASTIC BEAHVIOR OCCURS WHEN THE MATERIAL COMPLETELY LOST IT'S DUCTILITY. IN THE ABOVE MENTIONED GRAPH PLASTIC BEHAVIOR OCCUR DURING UNLOADING AFTER POINT "a".

    4) NON-LINEAR ELASTIC BEHAVIOR : 

    NON-LINEAR INELASTIC BEHAVIOR OCCURS AFTER THE LINE FROM "O" TENDS TO BENDS TOWARDS POINT "a" .

    ANSWER 3:  EXPLAIN MASS, STIFFNESS  AND DAMPING  COMPONENT IN THE EQUATION OF MOTION .

    STIFFNESS ,DAMPING ,AND MASS COMPONRNT :

    THE SDOF SYSTEM CAN BE VIEWED AS A COMBINATION OF THREE PURE , INDEPENDENT SYSTEM : 

    1) THE STIFFNESS COMPONENT : THE FRAME IS WITHOUT  DAMPING OR MASS . THE EXTERNAL FORCE "fs"  ON THE STIFFNESS COMPONENT IS RELATED TO DISPLACEMENT "u"  BY   "fs=Ku  , if the system linearly elastic.

     2) THE DAMPING COMPONENT : THE FRAME WITH ITS DAMPING PROPERTIES BUT NO STIFFNESS OR MASS . THE EXTERNAL FORCE ON THE DAMPING  COMPONENT IS RELATED TO VELOCITY BY "fd= CV ".

     3) THE MASS COMPONENT : THE ROOF MASS WITHOUT THE STIFFNESS OR DAMPING OF THE FRAME. THE EXTERNAL FORCE "fi"  ON THE MASS COMPONENT IS RELATED TO THE ACCELERATION BY fi =m ( m^double dot.) 

    EQUATION OF MOTION : EXTERNAL FORCES :

    IN FIG . SHOW IDEALIZED ONE STORY FRAME INTRODUCS EARLIER SUBJECTED TO EXTERNALY APPLIED FORCE p(t)   IN  THE DIRCETION OF DOF "u" . THIS NOTATION INDICATES THAT THE FORCE "p" varies WITH TIME "t".   THE RESULTING DISPLACMENT OF THE MASS ALSO VARIES WITH TIME (t) , IT IS DENOTED BY u(t) . 

    WE DRIVE THE DIFFERENTIAL EQUATION GOVERNING THE DISPLACEMENT u(t)  BY TWO METHOD USING 

    1. NEWTON'S SECOND LAW OF MOTION .

    2. DYNAMIC EQUILIBRIUM . 

     USING THE NEWTON'S SECOND LAW OF MOTION : 

    EXTERNAL FORCE= p(t) 

    ELASTIC OR (INELASTIC) FORCE (fs) 

    DAMPING RESTING FORCE f(D) 

    DISPLACEMENT FORCE U(t) 

    VELOCITY U(t) 

    1. ACCELERATION U"(t) 

    THE RESULTING FORCE ALONG THE X-AXIS 

    P-fs -f(D) =mu"  OR 

    mu"+ f(D) + fs = p(t) 

    put this equation in fs =k(u) and f(D) = CU" 

    NOW RESULT : mu"+cu"+fs =p(t)  OR

                             mu" +cu+ku= p(t)

    ANSWER 4) PROVIDE RELATIONSHIP BETWEEN NATURAL PERIOD (Tn) & NATURAL FREQUENCY (f) , AND PROVIDE THEIR DEFINITIONS.

    1. NATURAL PERIOD OF VIBRATION (Tn) : 

    THE TIME REQUIRED FOR THE UNDAMPED SYSTEM TO COMPLETE ONE CYCLE OF FREE VUBRATION (UNIT IN SECOND ) .

    IT IS RELATED TO THE NATURAL (Wn), IN UNITS OF RADIANS PER SECONDS .

    Tn = 2`(pi/Wn).

    2.NATURAL CYCLIC FREQUENCY (f) .

     

    fn =(1/Tn) 

    THEREFORE ; THE RELATION BETWEEN NATURAL PERIOD OF VIBRATION OF THE SYSTEM (Tn) AND NATURAL FREQUENCY (fn)  IS fn = (1/Tn ) .`

    ANSWER 5. EXPLAIN THE DETAILS ABOUT RESPONSE SPECTRUM & ITS GRAPH .

    RESPONSE SPECTRUM : 

    • It’s the central concept in earthquake engineering, provides a convenient means to summarize the peak response of all possible linear SDF systems to a particular component of ground motion.
    • It provides a practical approach to apply the knowledge of structural dynamics to the design structures and development of lateral force requirements in building codes.
    • A plot of the peak value of a response quantity as a function of the natural vibration period Tn of the system, or a related parameter such as circular frequency ωn or cyclic frequency fn, is called the response spectrum for that quantity. 
    • Each such plot is for Single Degree of Freedom systems having a fixed damping ratio Շ, and several such plots for different values of Շ are included to cover the range of damping values encountered in actual structures. 
    • A variety of response spectra can be defines depending on the response quantity is plotted. Consider the following peak responses.
    • The deformation response spectrum is a plot of uo against Tn for fixed Շ (damping ration). A similar plot for ůo is the relative velocity response spectrum, and for űto is the acceleration response spectrum.

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